riddler-castles/castle-solutions-3: 887
Data license: CC Attribution 4.0 License · Data source: fivethirtyeight/data on GitHub · About: simonw/fivethirtyeight-datasette
rowid | Castle 1 | Castle 2 | Castle 3 | Castle 4 | Castle 5 | Castle 6 | Castle 7 | Castle 8 | Castle 9 | Castle 10 | Why did you choose your troop deployment? |
---|---|---|---|---|---|---|---|---|---|---|---|
887 | 1 | 1 | 2 | 10 | 1 | 8 | 8 | 9 | 26 | 34 | First I wanted to beat all 5 of the top 5 from the last time. Then I wanted to beat the build optimized to beat them. Then I wanted to beat the build optimized to beat that. After that I still had 42 troops left, so I started thinking about what I lose to. I lose to builds that are stronger on any of 6,7,8. The way to beat this could be either increase my 6-7-8 numbers or pick up points from elsewhere from that person. I decided that playing for the 9 might be a good idea. The 9 was really expensive last time, but it was enabled to do so by the low 6-7-8 numbers. I'm assuming that this person is beating some or all of my 6-7-8, so they can't shove on the 9 as well. I've fairly arbitrarily decided 26 on the 9. This leaves me 16. First, I'm putting at least 1 on each of the first 5 to punish any 0s. Now I have 11. I might want to put everything on 5, and that would be strong against people who were playing around the previous set where 5 was a huge spike for no reason, but the 5 could easily be a huge spike again for no reason so I don't want to put much into it. The 4 seems like a significantly better spot because it was lower the last time but still part of the spike which means people playing around the last time will avoid it. I'm putting 9 more (10 total) on the 4, leaving me 2 left to place. 1 is going on the 3 to play around 1s and the other is going on the 8 to put it at 9 because I was scared I would lose the 8. |